8.37*10-4 mols Ni2+ / 8.37*10-4 mols Ni2+ = 1 Ni2+ 1.19*10-3 mols en /  8.37*10-

8.37*10-4 mols Ni2+ / 8.37*10-4 mols Ni2+ = 1 Ni2+
1.19*10-3 mols en /  8.37*10-4 mols Ni2+ = 1.42 ~ 1 en
5.67*10-3moles / 8.37*10-4 mols Ni2+ = 6 H2O
8.37*10-4moles SO42- / 8.37*10-4 mols Ni2+ = 1 SO42-
What would the empirical formula be?
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