# The angular position of a point on the rim of a rotating wheel is given by θ = 9

The angular position of a point on the rim of a rotating wheel is given by θ = 9.0t – 3.0t2 + t3, where θ is in radians and t is given in seconds.(a) What is the angular velocity at t = 6 s?1 rad/s (b)What is the angular velocity at t = 8.0 s?2 rad/s (c) What is the average angular acceleration for the time interval that begins at t = 6 s and ends at t = 8.0 s? 3 rad/s2(d) What is the instantaneous angular acceleration at the beginning of this time interval?4 rad/s2(e)What is the instantaneous angular acceleration at the end of this time interval? 5 rad/s2 (at the end)

The angular position of a point on the rim of a rotating wheel is given by θ = 9.0t – 3.0t2 + t3,where θ is in radians and t is given in seconds.(a) What is the angular velocity at t = 6 s?1…